[NewCandle] NR attempt at Fred's battery anti-lifter

[Nick Reiter]

Hi Fred,

The dry penny, when added to the dry paper at the
beginning of the sequence equalled the 10.62g
resultant weight minus the previous weight of 7.64g =
2.98 grams.

So ya, 2 grams plus for a penny is fine.

By taking the initial weight addition contributed by
the penny on the dry part of the towel, I presumed
that no galvanic effect would be at play, and thus the
weight would be a true tare.  Your protocol for
activating or de-activating the effect appeared to be
moving the penny on-to and off of the wet spot, so I
figured I was safe.

Back in the day, I had done some experiments with Sam
Faile that involved me weighing all individual
components in an isolated fashion, then putting them
together in the final "cluster" or arrangement. 
Sometimes the sum of the parts was more or less than
the aggregate.  However this was a PRECARIOUS thing to
do, as working in the tens of milligrams weight arena
makes things like hand moisture, dust specks, dirt
from the table, and small charges all accountible.

So thats why I avoid that approach unless geometry
dictates it must be done that way.  I tried to stick
as close as I could to my interpretation of your
words.

All the best,

N


--- Frederick Sparber <fsparber at gmail.com> wrote:

> Weight sequence:
> 
> Nick wrote;
> 
> "aluminum pan only - 4.26g
> add paper towel square - 6.14g tot.
> add salt water spot - 7.64g tot.
> add penny to dry area - 10.62g tot.
> move penny to wet area - 10.62g tot.
> wait 1 minute - 10.62g tot.
> penny to dry area - 10.61g tot.
> penny to wet area - 10.61g tot.
> penny dry - 10.61g
> penny wet - 10.61g
> penny dry - 10.61g
> penny wet - 10.61g
> penny dry - 10.61g
> wait 1 minute - 10.60g
> penny wet - 10.60
> penny dry - 10.60"
> 
> What did you dry penny weigh alone, Nick.
> 
> I get 2+ grams tops for all pennies I've weighed.
> According to this you
> might be
> throwing the baby out with the bath water.
> 
> Contact potential through wet or dry paper should
> make the aluminum pan
> positive
> in which case the earth's megacoulomb "excess
> negative charge" 100 volt per
> meter fair weather
> field should make it weigh more. F = E*Q  at 0.5
> grams  0.0049 newtons
> Q = 0.000049 Coulombs
> 
> Since Q = CV at 0.1 volt contact potential
> capacitance C = Q/0.1 = 490
> microfarads
> 
> Fred
> 
> http://www.micromagazine.com/archive/05/01/yang.html
> > _______________________________________________
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> NewCandle at ipdiscover.com
>
http://ipdiscover.com/mailman/listinfo/newcandle_ipdiscover.com
> 



       
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